y^2 = 4px has
vertex at (0,0)
focus at (p,0)
directrix at x = -p
The distance from focus to directrix is thus 2p, and the vertex is at (1,3)
So the parabola must be
(y-3)^2 = -12(x-1)
see the graph at
https://www.wolframalpha.com/input/?i=parabola+%28y-3%29%5E2+%3D+-12%28x-1%29
fill out the equation of a parabola with the focus of (-2,3) and the directrix is x=4
1 answer