p q ~p (~p --> q) q (~p --> q) ^ q
T T F T T T
T F F T F F
F T T F T T
F F T T T T
Based on the truth table, this statement is a contingency statement. It is neither a tautology (always true) nor a contradiction (always false), as the truth values vary depending on the inputs for p and q.
Fill in the truth table for the statement (~pq) q. You will need to create a truth table with additional columns as part of your work.
p q (~p-->q)^q
TT_ _
TF_ _
FT_ _
FF_ _
Based on your truth table, what type of statement is this?
Of Tautology
Contradiction
Contingent Statement
1 answer
1 answer