9x2 - 2x2 = 7x2
$x - 12x = -11x
$13 - 2 = 11
So the filled-in values are:
9x2 + x + 13
– 2x2 + 12x + 2
= 7x2 - 11x + 11
Fill in the missing values to show that polynomials form a closed system under subtraction.
9x2 + $$x + 13
– 2x2 + 12x + $$
$$x2 + 5x + 2
5 answers
wrong
I apologize for the mistake. Let's correct it:
9x^2 - 2x^2 = 7x^2
x - 12x = -11x
13 - 11 = 2
So, the correct values are:
9x^2 + x + 13
- 2x^2 + 12x + 11
= 7x^2 - 11x + 2
9x^2 - 2x^2 = 7x^2
x - 12x = -11x
13 - 11 = 2
So, the correct values are:
9x^2 + x + 13
- 2x^2 + 12x + 11
= 7x^2 - 11x + 2
9x^2 + (?)x + 13
- 2x^2 + 12x + 2
= 7x^2 + (?)x + 11
To fill in the missing terms:
9x^2 - 2x^2 = 7x^2
For the missing term in the x coefficient: x - 12x = -11x
And for the missing term in the constant: 13 - 2 = 11
Therefore, the filled in values are:
9x^2 + (-11)x + 13
- 2x^2 + 12x + 2
= 7x^2 + (-11)x + 11
= 7x^2 + (?)x + 11
To fill in the missing terms:
9x^2 - 2x^2 = 7x^2
For the missing term in the x coefficient: x - 12x = -11x
And for the missing term in the constant: 13 - 2 = 11
Therefore, the filled in values are:
9x^2 + (-11)x + 13
- 2x^2 + 12x + 2
= 7x^2 + (-11)x + 11