fill in the missing fractions to create a true equation.

Question

?/5-1/2=3/?

Answer 1

Let's assume the missing fractions are represented by a/b and c/d.

The equation ?/5 - 1/2 = 3/?

Multiplying both sides of the equation by the LCM (Least Common Multiple) of the denominators will help us eliminate the denominators.

LCM(5, 2) = 10.

So, multiplying all the terms by 10, we get:

(10/5) - (10/2) = (3/?) * 10

2 - 5 = (3/?) * 10

-3 = 30/?

Now we can cross-multiply:

-3 * ? = 30

-3? = 30

Dividing both sides by -3:

-3?/-3 = 30/-3

? = -10

Therefore, the missing fractions are -10/5 and -10/2.

-10/5 - 1/2 = 3/10

Answer 2

answer was

2/5-1/2=3/10

Answer 3

Apologies for the confusion. Let's solve the equation using your answer:

Step 1: Simplify the given equation: 2/5 - 1/2 = 3/10

To find the missing fraction, let's assume it is represented by a/b.

Step 2: The denominators on both sides are 5 and 2, so the denominator for the missing fraction will be the LCM of 5 and 2, which is 10.

Step 3: Rewrite the equation with the common denominator 10:

2/5 - 1/2 = 3/10

Step 4: To proceed, let's eliminate the fractions by multiplying each term by 10:

10 * (2/5) - 10 * (1/2) = 10 * (3/10)

Step 5: Simplify the equation:

4 - 5 = 3

Step 6: Solve for the missing numerator:

-1 = 3

Since -1 is not equal to 3, this equation does not have a solution.

Therefore, the given equation 2/5 - 1/2 = 3/10 does not have a true solution when the missing fractions are in the form a/b.