Fill in the blanks!

Question

Using the standard Method to Multiply a Two-Digit Number by a One-Digit Number
Find the product of 22 x 3
Write it vertically. The number with more digits goes on top, and the _ values should be lined up.

22
x3
----
___

Now, write the problem in expanded form.
(20 + _) x 3
(20 x _) + (2x3)
_+6
66

Answer 1

Let's fill in the blanks step-by-step.

1. We start with the multiplication set up vertically:

  22
x  3
-----

2. The blank under the line will be filled with the product of 22 and 3. Now, let's perform the multiplication.

3. Next, we write the problem in expanded form:

• For the tens place: \(20\)
• For the ones place: \(2\)

So the expanded form looks like this: \[ (20 + 2) x 3 \]

4. Distributing \(3\) to both terms in the parentheses, we have: \[ (20 x 3) + (2 x 3) \]

5. Now let's calculate each part:

• \(20 x 3 = 60\)
• \(2 x 3 = 6\)

So, the equation will be: \[ 60 + 6 \]

6. Finally, summing these gives: \[ 66 \]

Now, filling in the blanks:

The original multiplication layout is:

  22
x  3
-----
  66

The expanded form is: \[ (20 + 2) x 3 \] And the final calculation is: \[ 60 + 6 \] Resulting in: \[ 66 \]

So the filled blanks are:

• (20 + 2) x 3
• (20 x 3) + (2 x 3)
• 60 + 6
• 66