To solve the problem \( \frac{7}{3} \div \frac{2}{3} \), you can multiply by the reciprocal:
\[ \frac{7}{3} \div \frac{2}{3} = \frac{7}{3} \times \frac{3}{2} \]
Now, multiply the fractions:
\[ \frac{7 \times 3}{3 \times 2} = \frac{21}{6} \]
Next, simplify \( \frac{21}{6} \):
\[ \frac{21}{6} = \frac{7}{2} = 3 \frac{1}{2} \]
So, \( \frac{7}{3} \div \frac{2}{3} \) equals \( 3 \) whole groups and \( \frac{1}{2} \) as the fractional part.
Now, filling in the blanks:
- I have 3 of a group left over.
- I have \(\frac{1}{2}\) of a group left over.
Therefore, the complete statement is:
\( \frac{7}{3} \div \frac{2}{3} = 3 \) whole groups and \( \frac{1}{2} \) fractional part. I have \( \frac{1}{2} \) of a group left over.