Fill in the blanks and solve the problem.

Question

7/3 ÷ 2/3
7 thirds divided by 2 thirds equals ? whole groups and 1 fractional part.
I have ? of a group left over.

Answer 1

To solve the problem \( \frac{7}{3} \div \frac{2}{3} \), you can multiply by the reciprocal:

\[ \frac{7}{3} \div \frac{2}{3} = \frac{7}{3} \times \frac{3}{2} \]

Now, multiply the fractions:

\[ \frac{7 \times 3}{3 \times 2} = \frac{21}{6} \]

Next, simplify \( \frac{21}{6} \):

\[ \frac{21}{6} = \frac{7}{2} = 3 \frac{1}{2} \]

So, \( \frac{7}{3} \div \frac{2}{3} \) equals \( 3 \) whole groups and \( \frac{1}{2} \) as the fractional part.

Now, filling in the blanks:

1. I have 3 of a group left over.
2. I have \(\frac{1}{2}\) of a group left over.

Therefore, the complete statement is:

\( \frac{7}{3} \div \frac{2}{3} = 3 \) whole groups and \( \frac{1}{2} \) fractional part. I have \( \frac{1}{2} \) of a group left over.