To balance the equation \( 2Ag_2O → _Ag + _O_2 \), we can follow these steps:
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Start with the left side:
- There are 2 Ag2O, which means there are \( 2 \times 2 = 4 \) Ag atoms and \( 2 \times 1 = 2 \) O atoms.
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On the right side, to balance the O atoms, we need 2 O atoms. Since there is 1 O2 molecule, we can write 1 O2.
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We need to balance the Ag atoms. We have 4 Ag atoms on the left, so we need 4 Ag atoms on the right side.
Putting it all together, we have:
\( 2Ag_2O → 4Ag + 1O_2 \)
Thus, the filled in blanks would be:
- 4 for Ag
- 1 for O2
So the final answer is: 2Ag2O → 4Ag + 1O2.