To find the median, we first need to arrange the numbers in each class in ascending order:
Class 1: 0, 1, 1, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 8, 10
Class 2: 0, 0, 1, 2, 2, 2, 3, 3, 4, 5, 6, 6, 7, 9, 10
Since each class has 15 students, the median for each class will be the middle value when arranged in ascending order. In this case, the median will be the average of the two middle values if there is an even number of values.
For Class 1, the median is the 8th value, which is 5.
For Class 2, the median is the average of the 8th and 9th values, which are both 3, so the median is (3+3)/2 = 3.
Therefore, Class 1 has a higher median number of books read during the summer.
Fifteen students are randomly selected from two different classes. They were asked how many books they read during the summer. Their responses are as follows. Find the median number of books read by each class. Which class has a higher median number of books read?
Class 1: 0, 5, 3, 6, 7, 8, 10, 1, 1, 4, 5, 6, 4, 5, 6
Class 2: 2, 2, 4, 3, 0, 0, 6, 7, 10, 9, 6, 5, 3, 1, 2
(2 points)
The median number of books read during the summer by Class 1 is
The median number of books read during the summer by Class 2 is
Class has a higher median number of books read during the summer.
1 answer