430kcal=Mass*1kilocal/kg*(37-0)
masswater= 430kg/37
assume denstiy water is 1kg/liter
so that is 430/37 liters
2. 240*4186J=2.42E6J/kg*mass water
solve for mass of sweat.
few other questions.
1.) Suppose you expend 430 kilocalories during a long walk, how many liters of ice water at 0 degrees do you need to consume in order to use up the 430 kilocalories of metabolic energy. Stomach can hold 1 liter.
2. A person eats a container of strawberry yogurt. The Nutritional Facts label states that it contains 240 calories (a calorie = 4186 J). What mass of perspiration would one have to lose to get rid of this energy. Latent heat of vaporization of water is 2.42*10^6.
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