Felicia rewrote a quadratic function in vertex form.

h(x)= x^2−6x+7

Step 1: h(x)= (x^2−6x+ )+7

Step 2: h(x)=(x^2−6x+ 9 )+7 −9

Step 3: h(x)=(x−3 )^2+2
Felicia said that the vertex is (3, 2). Is Felicia correct? If not, identify the step in which Felicia made the mistake and correct her work.

1 answer

Felicia made a mistake in Step 2. The correct completion of the square for x^2 - 6x is +9, not -9.

So, the correct vertex form of the quadratic function h(x) is:
h(x) = (x - 3)^2 + 2

Therefore, Felicia's vertex of (3, 2) is correct.
Similar Questions
  1. Felicia rewrote a quadratic function in vertex form.h(x)= x^2−6x+7 Step 1: h(x)= (x^2−6x+ 9 )+7 Step 2: h(x)=(x^2−6x+ 9
    1. answers icon 1 answer
  2. Felicia rewrote a quadratic function in vertex form.h(x)= x2−6x+7 Step 1: h(x)= (x2−6x+ 9 )+7 Step 2: h(x)=(x2−6x+ 9 )+7
    1. answers icon 1 answer
  3. April rewrote a quadratic function in vertex form.h(x)=5^2-30x+30 step 1 h(x)=5(x^2-6x+ )+30 step 2 h(x)=5(x^2-6x+9)+30-45 step
    1. answers icon 2 answers
  4. Cole rewrote a quadratic function in vertex form.h(x)= x^2 - 6x + 7 Step 1: h (x) = (x^2 - 6x + ) + 7 Step 2: h (x) = (x^2 -
    1. answers icon 7 answers
more similar questions