This is a limiting reagent (LR) problem. I know that because amounts are given for BOTH reactants. First, balance equation.
2FeCl3(aq) + 3K2S(aq) ==> Fe2S3(aq) + 6KCl(aq)
mols FeCl3 = M x L = ?
mols K2S = M x L = ?
Using the coefficient in the balanced equation, convert mols FeCl3 to mols Fe2S3.
Do the same for mols K2S to mols Fe2S3.
It is likely that these two value will not agree which means one of them is wrong; the correct value in LR problems is ALWAYS the smaller value and the reagent producing that value is the LR.
Now convert mols Fe2S3 to grams. g = mols x molar mass.
FeCl3(aq) + K2S(aq) Fe2S3(aq) + KCl(aq)
Consider the unbalanced equation above.
What is the maximum mass of Fe2S3 that can be produced when 54.5 mL of 0.480 M FeCl3 and 98.5 mL of 0.420 M K2S react?
1 answer
1 answer