To calculate the total mass of the reactants in the reaction given by:
\[ \text{FeCl}_3 + 3\text{H}_2\text{O} \rightarrow \text{Fe(OH)}_3 + 3\text{HCl} \]
we need to find the molar masses of all the reactants, which are \( \text{FeCl}_3 \) and \( 3\text{H}_2\text{O} \).
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Calculate the mass of \( \text{FeCl}_3 \):
- Iron (Fe): 1 atom × 56 amu = 56 amu
- Chlorine (Cl): 3 atoms × 35 amu = 105 amu
- Total mass of \( \text{FeCl}_3 \): \[ 56 \text{ amu} + 105 \text{ amu} = 161 \text{ amu} \]
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Calculate the mass of \( 3\text{H}_2\text{O} \):
- Hydrogen (H): 2 atoms × 3 molecules = 6 atoms × 1 amu = 6 amu
- Oxygen (O): 3 atoms × 16 amu = 48 amu
- Total mass of \( 3\text{H}_2\text{O} \): \[ 6 \text{ amu} + 48 \text{ amu} = 54 \text{ amu} \]
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Calculate the total mass of the reactants:
- Total mass of reactants = mass of \( \text{FeCl}_3 \) + mass of \( 3\text{H}_2\text{O} \): \[ 161 \text{ amu} + 54 \text{ amu} = 215 \text{ amu} \]
So, the total mass of the reactants is 215 amu.
The answer is 3. 215 amu.