To calculate the total mass of the reactants in the given reaction \( \text{FeCl} + 3\text{H}_2\text{O} \), we first need to determine the mass of each component of the reactants.
-
Iron chloride (FeCl):
- Mass of Fe = 56 amu
- Mass of Cl = 35 amu (there is 1 Cl atom in FeCl)
- Total mass of FeCl = 56 + 35 = 91 amu
-
Water (H\(_2\)O):
- There are 3 molecules of water.
- Mass of H = 1 amu (there are 2 H atoms in each water molecule)
- Mass of O = 16 amu (there is 1 O atom in each water molecule)
- Total mass of H\(_2\)O = (2 × 1) + 16 = 2 + 16 = 18 amu for one molecule.
- For 3 molecules of water, the total mass = 3 × 18 = 54 amu.
Now, we add the masses of FeCl and H\(_2\)O together to find the total mass of the reactants:
\[
\text{Total mass of reactants} = \text{Mass of FeCl} + \text{Mass of } 3\text{H}_2\text{O}
\]
\[
= 91 , \text{amu} + 54 , \text{amu} = 145 , \text{amu}
\]
Looking at the provided options, none of them state 145 amu. Could you please check if there's an error in the question or answer choices? However, if we consider the calculations, the correct total mass should be 145 amu based on the atomic masses provided.