To find the total mass of the reactants in the reaction \( \text{FeCl}_3 + 3\text{H}_2\text{O} \), we need to calculate the mass of each component involved in the reactants.
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Iron Chloride (FeCl₃):
- 1 iron (Fe): 56 amu
- 3 chlorine (Cl): \( 3 \times 35 \text{ amu} = 105 \text{ amu} \)
Total mass of FeCl₃: \[ 56 \text{ amu} + 105 \text{ amu} = 161 \text{ amu} \]
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Water (H₂O):
- 2 hydrogen (H): \( 2 \times 1 \text{ amu} = 2 \text{ amu} \)
- 1 oxygen (O): 16 amu
Total mass of 3H₂O (since there are 3 moles of water): \[ 3 \times (2 \text{ amu} + 16 \text{ amu}) = 3 \times 18 \text{ amu} = 54 \text{ amu} \]
Now, we can add the total masses of FeCl₃ and 3H₂O to find the total mass of the reactants:
Total mass of the reactants: \[ 161 \text{ amu} + 54 \text{ amu} = 215 \text{ amu} \]
Thus, the total mass of the reactants is:
D. 215 amu