4Fe + 3O2 --> 2Fe2O3
mols O2 = 80 mL x (1 mol/22,400 mL) = ?
Using the coefficients in the balanced equation, convert mols O2 to mols Fe.
Then convert mols Fe to grams. g = mols x atomic mass Fe.
Fe + O2--->Fe2O3
How many grams of iron are required to convert 80 mL of oxygen at STP?
1 answer