To compare the kinetic energies of Watermelon A and Watermelon B, we can use the formula for kinetic energy (KE):
\[ \text{KE} = \frac{1}{2} mv^2 \]
where \( m \) is the mass and \( v \) is the speed.
For Watermelon A:
- Mass = 4 kg
- Speed = 2 m/s \[ \text{KE}_A = \frac{1}{2} \times 4 \times (2^2) = \frac{1}{2} \times 4 \times 4 = 8 , \text{Joules} \]
For Watermelon B:
- Mass = 4 kg
- Speed = 4 m/s \[ \text{KE}_B = \frac{1}{2} \times 4 \times (4^2) = \frac{1}{2} \times 4 \times 16 = 32 , \text{Joules} \]
Now we can compare the kinetic energies:
- Kinetic Energy of Watermelon A = 8 Joules
- Kinetic Energy of Watermelon B = 32 Joules
Conclusion: Watermelon B has more kinetic energy.
Thus, the correct response is: The watermelon B has more kinetic energy.