Factorize x2+4xy+4y2-9x2y2

3 answers

x^2 + 4xy + 4y^2 - 9x^2y^2
= (x+2y)^2 - 9x^2 y^2
= (x+2y)^2 - (3xy)^2
now you have a difference of squares
= (x+2 + 3xy)(x+2 - 3xy)
if x = 2, y = -1, then the value of x^2 + 4xy + 4y^2 is
Good
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