Factorize 16x^2 - 16x + 58 = 0

Answer 1

To factorize the quadratic equation 16x^2 - 16x + 58 = 0, we first need to find the factors of the equation by using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

Where a = 16, b = -16, and c = 58

Plugging the values into the formula:

x = (16 ± √((-16)^2 - 4*16*58)) / 2*16
x = (16 ± √(256 - 3712)) / 32
x = (16 ± √(-3456)) / 32
x = (16 ± 4i√216) / 32
x = (1 ± i√216) / 2

Therefore, the factors are:

(x - (1 + i√216)/2)(x - (1 - i√216)/2)