Factorise x^4-x^2y-6y^2 Thanks to whoever solves it

1 answer

x⁴ - x² ∙ y - 6 ∙ y² =

x² ∙ x² - x² ∙ y - 6 ∙ y² =

x² ∙ x² - 3 x² ∙ y + 2 x² ∙ y - 2 ∙ y² ∙ 3 =

x² ∙ x² - 3 x² ∙ y + 2 y ∙ x² - 2 ∙ y ∙ y ∙ 3 =

x² ∙ ( x² - 3 y ) + 2 y ∙ ( x² - y ∙ 3 ) =

x² ∙ ( x² - 3 y ) + 2 y ∙ ( x² - 3 y ) =

( x² - 3 y ) ( x² + 2 y )

x⁴ - x² y - 6 y² = ( x² - 3 y ) ( x² + 2 y )
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