I do not know what you mean
x^3 + 1/(1/x^3)
or what you said which is
x^3 + 1 + 1/x^3
????
if the first multiply top and bottom of second term by x^3
x^3 + x^3/1
= 2x^3
Factorise x^3+1/1/x^3 (i.e x cubed plus 1 and 1 over x cubed) how is it done? Thanks
3 answers
According to your wording,
(x^3 + 1) ÷ 1/x^3
which is
(x^3 + 1)(x^3)
= x^3(x+1)(x^2 - x + 1) , using the factoring of cubes principle
(x^3 + 1) ÷ 1/x^3
which is
(x^3 + 1)(x^3)
= x^3(x+1)(x^2 - x + 1) , using the factoring of cubes principle
It Is Factorise x^3 + one whole number and a fraction 1/(x^3) just like e.g 1.5=1/1/2