To factorise the quadratic equation 2y^2 - 16y - 130, we need to find two numbers that multiply to -260 (2 * -130) and add up to -16.
The two numbers are -20 and 13.
Therefore, the factorised form of 2y^2 - 16y - 130 is:
2y^2 - 26y + 10y - 130
2y(y - 13) + 10(y - 13)
(2y + 10)(y - 13)
Factorise 2y squared - 16 y - 130
1 answer