factorise: 2x^2+6x-16, and 14x^2-3x-2.

Question

Solve: 6y^2-5y-6=0, and 8x^2-2x-1=0.
Rearrange: p=5t-u/u to make u the subject, and p(q+r)=(q-p).
please help i've done about 40 questions and im just stuck on these. thanks for the help

Answer 1

2x^2+6x-16
= 2(x^2 + 3x - 8)

14x^2-3x-2
= (2x - 1)(7x + 2)

6y^2 - 5y - 6 = 0
(3y + 2 )(2y - 3 ) = 0
y = - 2/3 or y = 3/2

8x^2-2x-1=0
(4x + 1)(2x - 1) = 0
x = - 1/4 or x = 1/2

p=5t-u/u
I think you mean p=(5t-u)/u or else the u's would cancel
up = 5t - u
up + u = 5t
u(p+1) = 5t
u = 5t/(p+1)

p(q+r) = (q-p)
you don't say which variable to solve for, but expand, bring the necessary variable to the left, factor it out like I did in the previous problem

Answer 2

thanks for the help but cant
2x^2+6x-16
= 2(x^2 + 3x - 8)

go any further

Answer 3

ps thanks Reiny