since you have 3u^2, look for multiples of 3:
3u^2-21u = 3u(u-7)
Work on that idea. But why both the -7 and +49 constant terms?
Looks like a typo to me.
Factor. Use factoring by grouping even though it would seem reasonable to first combine like terms
3u^2-7-21u+49
Would be the same procedure as factoring polynomial?
Thanks!
6 answers
That's the actual problem on my assignment.
I am so confused!
I am so confused!
Well, there must be a typo somewhere, because if we say -7+49 = 42, then we have
3u^2-21u+42
and that does not factor.
3u^2-21u+42
and that does not factor.
You are probably right but is what the question in the textbook is.
I am unsure of what the answer is.
I am unsure of what the answer is.
I'll admit that if the question is unclear, so will be the answer.
Better check with your teacher.
Better check with your teacher.
OK I will gt in touch with the teacher.
Thanks!
Thanks!