To factor the expression \( 24y^4 - 6y^2 \), we can follow these steps:
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Identify and factor out the greatest common factor (GCF): The GCF of the coefficients \( 24 \) and \( 6 \) is \( 6 \). Additionally, both terms include \( y^2 \) as a factor. Therefore, the GCF is \( 6y^2 \).
We can factor this out: \[ 24y^4 - 6y^2 = 6y^2(4y^2 - 1) \]
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Factor the remaining expression if possible: The expression \( 4y^2 - 1 \) is a difference of squares. It can be factored further as: \[ 4y^2 - 1 = (2y - 1)(2y + 1) \]
Now we can combine everything:
So the completely factored form of the expression \( 24y^4 - 6y^2 \) is: \[ 6y^2(2y - 1)(2y + 1) \]