Factor the Polynomial in quadratic form.
6y(to the sixth power) - 5y(to the third power) - 4
6y^6 - 5y^3 -4
= (2y^3 + 1)(3y^3- 4)
I do not believe the cubic terms are separable into quadratic factors.
6y(to the sixth power) - 5y(to the third power) - 4
6y^6 - 5y^3 -4
= (2y^3 + 1)(3y^3- 4)
I do not believe the cubic terms are separable into quadratic factors.
1 answer
1 answer
1 answer
1 answer