To factor the polynomial \( 2x^5 - 4x^3 + 2x \) and solve the equation \( 2x^5 - 4x^3 + 2x = 0 \), we can first factor out the common term:
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Factor out the greatest common factor:
\[ 2x^5 - 4x^3 + 2x = 2x(x^4 - 2x^2 + 1) \]
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Now we have:
\[ 2x(x^4 - 2x^2 + 1) = 0 \]
This gives us one solution: \( x = 0 \).
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Next, we need to factor the quadratic-like expression \( x^4 - 2x^2 + 1 \). We can substitute \( y = x^2 \):
\[ y^2 - 2y + 1 = (y - 1)^2 \]
Substituting back \( y = x^2 \):
\[ (x^2 - 1)^2 = (x - 1)^2(x + 1)^2 \]
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Combine all the factors:
\[ 2x(x - 1)^2(x + 1)^2 = 0 \]
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Find the solutions from the factors:
- From \( 2x = 0 \), we get \( x = 0 \).
- From \( (x - 1)^2 = 0 \), we get \( x = 1 \) (with a multiplicity of 2).
- From \( (x + 1)^2 = 0 \), we get \( x = -1 \) (with a multiplicity of 2).
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Thus, the solutions to the polynomial equation are:
\[ x = 0, \quad x = 1, \quad x = -1 \]
Final Answer:
The roots are \( x = 0, x = 1, x = -1 \).
Therefore, the correct response is: x = -1, x = 0, x = 1.