Asked by Juri
Factor out 8x^3y^6 + 27
One factor is 2xy^2+3. (The sum of the cube roots of the first and last terms). Use long division to compute
(8x^3y^6 + 27)/(2xy^2 + 3) to get the other factor
One factor is 2xy^2+3. (The sum of the cube roots of the first and last terms). Use long division to compute
(8x^3y^6 + 27)/(2xy^2 + 3) to get the other factor
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