Factor it completely

13x^11-117x^3

1 answer

To factor the expression \( 13x^{11} - 117x^3 \) completely, we can follow these steps:

  1. Factor out the greatest common factor (GCF): In this expression, both terms share a common factor of \( 13x^3 \).

    \[ 13x^{11} - 117x^3 = 13x^3 (x^8 - 9) \]

  2. Factor the difference of squares: The expression \( x^8 - 9 \) can be factored further, as it is a difference of squares:

    \[ x^8 - 9 = (x^4)^2 - 3^2 = (x^4 - 3)(x^4 + 3) \]

  3. Combine the factors: Substituting back, we have:

    \[ 13x^{11} - 117x^3 = 13x^3 (x^4 - 3)(x^4 + 3) \]

Since \( x^4 - 3 \) and \( x^4 + 3 \) do not factor further using real coefficients, we conclude our factorization here.

Thus, the completely factored form of the expression is:

\[ \boxed{13x^3 (x^4 - 3)(x^4 + 3)} \]