Factor each polynomial.

Question

1.q^6 - 169k⁴
2.128h^12 - 1250j^8
3.216 - m^12
4.24a^9 - 81b³

Answer 1

1.q^6 - 169k⁴ --- difference of squares
= (q^3 - 13k^2)(q^3 + 13k^2)

2.128h^12 - 1250j^8 --- common factor of 2, then difference of squares
= 2(64h^12 - 625j^8)

3.216 - m^12 ------ difference of cubes
= (6^3 - (m^4)^3 )
= (6 - m^4)(36 + 6m^4 + m^8)

4.24a^9 - 81b³
= 3(8a^9 - 27b^3) ---- I now see a difference of cubes
= ......

Answer 2

ware is the Sulotion