375x^3 - 192y^3
= 3(125x^2 - 64y^3)
I now recognize the last factor as a difference of cubes
= 3(5x-4y)(25x^2 - 100xy + 16y^2)
Factor completely, or state that the polynomial is prime.
375x^3 - 192y^3
1 answer
375x^3 - 192y^3
1 answer