A. You can factor out 3/√x to get
3/√x (x^2-3x+2)
3/√x (x-1)(x-2)
Or, if you don't want that extra 1/√x, now you can divide by it to get
3(√x - 1/√x)(x - 2)
or
3(x-1)(√x - 2/√x)
B.
xy(x^2-4)
xy(x-2)(x+2)
Factor completely:
A. 3x^3/2 -9x^1/2 +6x^-1/2
B. x^3 y -4xy
1 answer