looks like a common factor of 4y
can you finish it?
Factor Completely
8y^5+12y^3+4y
3 answers
So is it 4y(2y^4+3y^2+1) or 4y(y^2+1)(2y^2+1)
clearly
4y(y^2+1)(2y^2+1)
Always check your factored answer by expanding it again to make sure the original comes back
4y(y^2+1)(2y^2+1)
Always check your factored answer by expanding it again to make sure the original comes back
2 answers