Ask a New Question

factor completely. -49x^2-35x-6

Please help with this, I know you multiply the two outer numbers which =-294, I am just having trouble finding a pair of factors of 294 that sum add up to 35. thanks

1 answer

-49x^2-35x-6
-(49x^2+35x+6)
-(7x+2)(7x+3)

Ask a New Question or answer this question.

Similar Questions

Factor Completely:3t^3 + 5t^2 - 12t first take out the t so you have: t(3t^2 + 5t - 12) you should be able to factor it easily
1. 0 answers
Take any Three consecutive fibonacci numbers: multiply the outer Two numbers, Squre the inner one. Do this At Least 6 times.
1. 1 answer
1. Solve for x: 4x/9 = 2(x+4)/32. Factor completely : x to the fourth power -16... 3. If a = all #s between -5 and 5, B= all
1. 1 answer
Order the steps from first to last that would be used to factor: 3x^2 - 13x - 10Steps to organize: Find the two numbers that
1. 1 answer

more similar questions