Factor by grouping x^3-4x^2- 4x+16

A (x+4)(x+2)
B (x+4)(x^2-4)
C (x+4)(x^2-4)
D (x-4)(x-2)

1 answer

To factor the expression x^3 - 4x^2 - 4x + 16, we can use the method of grouping.

First, let's group the terms in pairs:

(x^3 - 4x^2) - (4x - 16)

Now, let's factor out the greatest common factor from each pair:

x^2(x - 4) - 4(x - 4)

Notice that we now have a common factor of (x - 4). Factoring this out, we get:

(x - 4)(x^2 - 4)

Next, we can further factor the expression x^2 - 4 as the difference of squares:

(x - 4)(x + 2)(x - 2)

So the factored form of the expression x^3 - 4x^2 - 4x + 16 is option C: (x + 4)(x^2 - 4).
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