The given expression is a quadratic trinomial in the form of \( ax^2+bx+c \).
We have \( 9u^2+12uv+4^2 \).
The factors of 9u^2 are 3u and 3u.
The factors of 4^2 are 2 and 2.
Now, we need to find two numbers that multiply to \( 9u^2\cdot4^2 = 36u^2 \) and add up to \( 12uv \).
The numbers are 6u and 6u.
Therefore, we can factor the expression as follows:
\( 9u^2+12uv+4^2 = (3u+2)(3u+2) = (3u+2)^2 \)
Factor:9u^2+12uv+4^2
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