First write this quadratic in its general form
v^2 + 17v - 72 = 0
I cannot find any two numbers that have a difference of 17 and multiply to get 72
Secondly, the discriminant value is
17^2-4(1)(-72) = 577
This is not a perfect square, so the equation has irrational roots, which means, that the equation does not factor over the rationals.
Factor
72-17v=v^2
3 answers
v^2 + 17 v -72 = 0
-17 +/- sqrt(289+288)
--------------------
2
= 8.5 +/- 12 approximately
BUT I bet you have a sign error
because if it were
v^2 + 17 v + 72 it would factor into
(v+8)(v+9) = 0
are you sure it is not -72 -17 v = v^2
-17 +/- sqrt(289+288)
--------------------
2
= 8.5 +/- 12 approximately
BUT I bet you have a sign error
because if it were
v^2 + 17 v + 72 it would factor into
(v+8)(v+9) = 0
are you sure it is not -72 -17 v = v^2
Thank you. I thought I was loosing my mind.
0 answers