Factor.

4u2–26u+22

2 answers

To factor 4u^2 - 26u + 22, we first need to find two numbers whose product is 4 * 22 = 88 and whose sum is -26.

One way to do this is by trial and error. Here is one possible method:

- Start with the factors of 88: 1, 2, 4, 8, 11, 22, 44, 88.
- Look for two numbers whose difference is 26 (the opposite of the sum we need). We can quickly eliminate some pairs by noticing that their difference is not even:
- 88 - 1 = 87
- 44 - 2 = 42
- 22 - 4 = 18
- 8 - 11 = -3 (this one works!)
- So we can break up -26u as -11u - 15u, and rewrite the expression as:
4u^2 - 11u - 15u + 22
- Now we can group the terms and factor by grouping:
(4u^2 - 11u) - (15u - 22)
u(4u - 11) - 5(3u - 2)
(4u - 11)(u - 5/3)

Therefore, 4u^2 - 26u + 22 factors as (4u - 11)(u - 5/3).
AAAaannndd the bot gets it wrong yet again!
clearly wrong, since -11-20/3 ≠ -26

Start by factoring out the 2
4u^2–26u+22 = 2(2u^2-13u+11)
Now it seems clear that we just need 2(2u-11)(u-1)