Asked by Lydia
f(x) = x2 + 11x, x ≥ − 11/2
find the inverse
find the inverse
Answers
Answered by
Steve
y = x^2+11x
for inverse, switch names and solve for y:
x = y^2+11y
y^2+11y-x = 0
y = (-11±√(121+4x))/2
with the original domain restricted to x >= -11/2, that means
y = -11/2 + √(121+4x)/2
or, consider that
y = x^2+11x
= (x+11/2)^2 - 121/4
restricting the domain to x >= -11/2 means we take just the right branch of the parabola. So, swapping names,
x = (y+11/2)^2 - 121/4
y+11/2 = +√(x + 121/4)
and we get the above result
for inverse, switch names and solve for y:
x = y^2+11y
y^2+11y-x = 0
y = (-11±√(121+4x))/2
with the original domain restricted to x >= -11/2, that means
y = -11/2 + √(121+4x)/2
or, consider that
y = x^2+11x
= (x+11/2)^2 - 121/4
restricting the domain to x >= -11/2 means we take just the right branch of the parabola. So, swapping names,
x = (y+11/2)^2 - 121/4
y+11/2 = +√(x + 121/4)
and we get the above result
Answered by
Anonymous
23
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