f(x)=x^3-3x^2-3x-8/(-3x^2-4x-6)

Find the equation of the non-vertical asymptote.
What is the smallest value of x at which f(x) intersects its non-vertical asymptote?

the non vertical asymptote is -1/3x + 13/9 i found that using synthetic division and i know there is an intersect its non-vertical asymptote but i don't know how to find it....

1 answer

I agree on the asymptote.

So set the intercepts equal..

-x/3+ 13/9= (x^3-3x^2-3x-8)/(-3x^2-4x-6)

+x^3 +4x^2/3+2x-13/3 x^2 -52/9x-26/3=x^3-3x^2-3x-8

combining terms
x^2 (4/3-13/3+3) +x(2+3 -52/9)-26/3+8=0

check that several times. then use the quadratic equation to solve for x
Similar Questions
    1. answers icon 2 answers
  1. f(x)=8x^3+1x^2–8x+2/–7x^2–4x+9Find the equation of the non-vertical asymptote. y = Does f(x) intersect its non-vertical
    1. answers icon 1 answer
  2. f(x)=[5x^3-4x^2-8x+9]/[2x^2-1x-3]Find the equation of the non-vertical asymptote. y = Does f(x) intersect its non-vertical
    1. answers icon 1 answer
  3. f(x)=[5x^3-4x^2-8x+9]/[2x^2-1x-3]Find the equation of the non-vertical asymptote. y = Does f(x) intersect its non-vertical
    1. answers icon 1 answer
more similar questions