horizontal slope means f' = 0
f'(x) = (3x-1)(x+1)
now it should be clear.
f(x)=x^3-2x^2+x and f'(x)=3x^2-4x+1
Find the value(s) of x where f(x) has a horizontal tangent (slope=0)
1 answer
Find the value(s) of x where f(x) has a horizontal tangent (slope=0)
1 answer