f(x)=(x^3-27)/(x^2-3x)

Question

I need to find the slant.

If the vertical asymptotes is x=0

then is the slant y=x+3?

Answer 1

f(x)=(x-3)(x+3)/x(x-3)= (x+3)/x
The vertical asymptote is indeed x=0
and the slanting asymptote is indeed the line y=x+3

Answer 2

f(x)=(x-3)(x^2+3x+9)/x(x-3)=
(x^2+3x+9)/x=x+3+9/x
If x->inf then 9/x->0