learly you are studying the quadratic function , which when graphed is a parabola.
One of the first things you learn is how to find the vertex. Go to your text or you class notes to look at the example and do the same thing.
F(x) = -x^2 - x +2
graph function identify the vertex and axis of symmerty.
Can some one explain the steps to get answer? I know I need to find the points on a graph just so confused
2 answers
f(x) = -(x^2+x-2)
= -(x+2)(x-1)
The roots are at -2 and +1
So, the vertex and the axis of symmetry are midway between the roots, at x = -1/2
Now just find the y-coordinate of the vertex.
= -(x+2)(x-1)
The roots are at -2 and +1
So, the vertex and the axis of symmetry are midway between the roots, at x = -1/2
Now just find the y-coordinate of the vertex.