f(x)=x + 2/x^2 -9 and g(x)=11/x^2+3x
(a) find f(x) + g(x)
(b) list all of the excluded values
(c) classify each type of discontinuity
To receive credit, this must be done by Algebraic methods, not graphing
Understand and Think : what is being asked in the problem and what does that mean?
same equation as first one
(a) find f(x) + g(x)
(b) list all of the excluded values
(c) classify each type of discontinuity
To receive credit, this must be done by Algebraic methods, not graphing
same equation
(a) find f(x) + g(x)
(b) list all of the excluded values
(c) classify each type of discontinuity
To receive credit, this must be done by Algebraic methods, not graphing
Determine the points of discontinuity for the following rational function.
y= x+3/x^2 +8x+15
What are the points of discontinuity? Select all that apply.
A. x=0
B. y= - 3
C. x= - 3
D. x= - 5
E. y =0
F. y= - 5
G. There are no points of discontinuity.
5 answers
f(x)=x + 2/x^2 -9 and g(x)=11/x^2+3x
so, just use these values to find (I'm assuming the usual carelessness with parentheses here, as well as the evidence of rational functions)
f(x) + g(x) = (x+2)/(x^2-9) + 11/(x^2+3x)
= (x+2) / (x+3)(x-3) + 11 / x(x+3)
Now the common denominator is x(x+3)(x-3) so we now have
[(x+2)(x) + 11(x-3)] / x(x^2-9)
= (x^2+13x-33) / x(x^2-9)
The excluded values are those where the denominator is zero, since division by zero is undefined.
Those would be x = -3, 0, 3
Since the numerator is not zero at any of those values, they are all vertical asymptotes (infinite discontinuities)
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y= x+3/x^2 +8x+15 = (x+3) / (x+3)(x+5)
Here, there are two discontinuities, at x = -3, -5
Note that there is a discontinuity at x = -3, but the simplified function is
y = 1/(x+5)
everywhere except at x = -3, since 0/0 is undefined. That means that there is a hole (removable discontinuity) at x = -3, which could be removed by defining y(-3) = 1/2
There is a vertical asymptote at x = -5 since y = 1/0 which is undefined and cannot be removed
(a) find f(x) + g(x)
(b) list all of the excluded values
(c) classify each type of discontinuity
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I guess maybe you mean:
f(x)= (x + 2) / (x^2 -9 ) and g(x)=11/(x^2+3x)
(a) find f(x) + g(x)
(b) list all of the excluded values
(c) classify each type of discontinuity
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f(x)= (x + 2) / [(x-3)(x+3]and g(x)=11/ x(x+3)
f(x)= x(x + 2) / x [(x-3)(x+3]and g(x)=11(x-3)/ [x(x+3)(x-3)]
f(x)= (x^2+2x) / x [(x-3)(x+3] and g(x)=(11x-33) / [x(x+3)(x-3)]
so f(x) + g(x)
= (x^2 +13 x -33) / [x(x+3)(x-3)]
That obviously explodes if x = 0 or x=3 or x = -3
trouble if x = -5
but what if before we simplified x=-3
we get 0 / 0 ?