Question

f(x) (x^2+lnx)(2+e^2)
derivative

also,

f(x)= (3x+x^4)^(3/2)/(7x^2-1)

Answer 1

for the first one, since 2+e^2 is a constant, you simply get

f'(x) = (2+e^2)(2x + 1/x)

(are you sure there was no typo ?)

for the 2nd use the quotient rule, give it a try, let me know what you got

Answer 2

the first one should be (x^2+lnx)(2+e^x) sorry

Answer 3

f(x) = (x^2+lnx)(2+e^x)

f'(x) = (x^2 + lnx)(e^x) + (2+e^x)(2x + 1/x)

I used the product rule,
expand and simplify if needed