f(x)=(x-2)^2 +3

Question

x | f(x)
1 | f(1)=
2 | f(2)=
3 | f(3)=
4 | f(4)=

Answer 1

To find the values of f(x) at each given x, we substitute the x-values into the function f(x)=(x-2)^2 + 3.

1 | f(1) = (1-2)^2 + 3
= (-1)^2 + 3
= 1 + 3
= 4

2 | f(2) = (2-2)^2 + 3
= (0)^2 + 3
= 0 + 3
= 3

3 | f(3) = (3-2)^2 + 3
= (1)^2 + 3
= 1 + 3
= 4

4 | f(4) = (4-2)^2 + 3
= (2)^2 + 3
= 4 + 3
= 7

Therefore, the values of f(x) at each given x are:
f(1) = 4
f(2) = 3
f(3) = 4
f(4) = 7