since f(x) is defined for x=2, it is just 2^2+1 = 5
for x>2, the limit would be (2-3)^2 = 1
Since the limits are not the same, you cannot have both
f(x)={x²+1 if x≤2
{(x-3)² if x≥2
it must be either
f(x)={x²+1 if x≤2
{(x-3)² if x>2
or
f(x)={x²+1 if x<2
{(x-3)² if x≥2
f(x)={x²+1 if x≤2
{(x-3)² if x≥2
They said
Lim x=>2^(-) f(x)=?
lim x=> 2^+ f(x)=?
But I don't know how
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