Since |x| = x when x >= 0
|x|= -x when x < 0
we need to find where f(x) >= 0 and f(x) < 0
f(x) = (x-7)(x+1)
f >= 0 where x <= -1 or x >= 7
This should get you going.
f(x)= the absolute value of x^2-6x-7
a) Find a piecewise defined function that has no absolute value involved
b) Let g(x)=f(x) for x is greater than or equal to 7 find an expression of
g^-1(x)
c. give the domain and range of g^-1(x)
1 answer
1 answer