f'(x) = e^x - 1
= 0 for extrema of the function
e^x = 1
x = 0
b) ??
c) for points of inflection, f''(x) = 0
f''(x) = e^x
e^x = 0
has no solution.
look at the graph of y = e^x, it never touches the x-axis
f(x)=e^x-x
(a) at what x-values does f have relative extrema?
(b) find the exact value of -1 to 1 on an interval f(x)dx.
(c) show that f does not have any inflection points.
1 answer