f(g) = (7g+28)/(g-3)
= (7(3x+28)/(x-7) + 28)/(3x+28)/(x-7) - 3)
= x
g(f) = (3f+28)/(f-7)
= (3(7x+28)/(x-3) + 28) / ((7x+28)/(x-3) - 7)
= x
How odd! However, if you solve for f-1(x) you get g(x) and vice-versa.
f(g(-1)) = f(-1) = -1
f(x)=(7x+28)/(x-3) and g(x)=(3x+28)/(x-7)
Find: (fog)(x)
(gof)(x)
(fog)(-1)
1 answer