f(-3) = 54 + 18 + 9 + 2 = 83
f(-1) = -2 + 2 + 3 + 2 = 5
slope = (5-83)/(-1+3) = -39
f ' (x) = -6x^2 + 4x - 3
then -6x^2 + 4x - 3 = -39
6x^2 - 4x -36 = 0
3x^2 - 2x - 18 = 0
x = (2 ± √220)/6
= appr 2.8054 or appr -2.1388
f(x) -2x^3+2x^2-3x+2
Find the average slope of this function on the interval (–3–1) ________ <--A
By the Mean Value Theorem, we know there exists a c in the open interval (–3–1) such that f'(c) is equal to this mean slope. Find the value of c in the interval which works _________ <--B
A=?
B=?
ty
1 answer
1 answer